Tuesday, September 18, 2012

Slant Height Square Pyramid


Introduction to slant height of a square pyramid:

Pyramid is one of the shapes in geometry. A square pyramid is a general pyramid consist of square base. It is octahedron type.The lateral edge length and slant height, s of a right square pyramid of side length and height are In pyramid, the outer surfaces are triangular and converge at a point. The base of pyramid can be any shape like triangular, square, rectangular or of any polygon shape. Pyramid is classified into Volume of a Pyramid, square pyramid, and rectangular pyramid. All types of pyramid have three triangular faces and a base. Let’s see about basic three shapes of pyramid.

Square Pyramid Figure

Types of pyramid: 

Square pyramid
Triangular pyramid and
Rectangular pyramid.


Formula for Square Pyramid Slant Height:

Formula for finding the slant height of square pyramid:

s² = h² + (b/2)²
here s, slant height
h, height of pyramid
b, base length

Understanding prime factorization practice problems is always challenging for me but thanks to all math help websites to help me out.

Example Problems in Square Pyramid Slant Height:

Ex 1:

The  square pyramid of height 24 cm. Find the slant height if the base edges are given as 14 cm.

Sol:
Formula for finding slant height will be  
h=24 and b=14 `b/2` =7
s² = h² +` (b/2)^2 `
s= `sqrt(24^2 + 7^2) `

= `sqrt(576 + 49)`

= `sqrt(625)`
= 25 cm

Ex 2:
The height of square pyramid 350 ft. and each side of  base is 646 ft. calculate the slant height length.

Sol:
given h=350 b=646 b/2=323
s² = h² + (b/2)²
s² = 350² + 323²
s² = 226829
s = 426.27 ft.

Ex 3:
The  square pyramid of height 32 cm. Find the slant height if the base edges are given as 12 cm.

Sol:
Formula for finding slant height will be  
h=32 and b=12 `b/2` =6
s² = h² +` (b/2)^2 `
s= `sqrt(32^2 + 6^2) `

= `sqrt(1024 + 36)`

= `sqrt(1060)`
= 32.55 cm
Ex 4:
The  square pyramid of height 16 cm. Find the slant height if the base edges are given as 4 cm.

Sol:
Formula for finding slant height will be  
h=16 and b=4 `b/2` =2
s² = h² +` (b/2)^2 `
s= `sqrt(16^2 + 4^2) `

= `sqrt(256 + 16)`

= `sqrt(272)`
= 16.5 cm

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