Random Variable X

Introduction to random variable:

The arithmetical value  of a variable is defined by an event,that variable is known as random variable.Random variable may be discrete or continuous.Discrete random variables contains the positive integer values that may exist between zero and infinity.Common example for discrete random variable is when we toss a coin,the possibility of getting head is the positive integer.In continuous random variable the value may range between zero and one sometimes it may be non-integer value.

Random Variable X
random variable x problem 3:

Select the number at random from 12 to 18. What is the probability for select the number is odd?

Solution

The random variables x of the above experiment is 12,13,14,15,16,17,18

i)Take P(A) is the probability of the odd number occur.

The random variable x of odd numbers are 13,15,17.So n(A)=3

Total outcomes n(S)=7

So P(x)=`(n(A))/(n(S))`

=`3/7` .

random variable x problem 4:

Select the number at random from 12 to 18. What is the probability for select the number is even?

Solution

The random variables x of the above experiment is 12,13,14,15,16,17,18

i)Take P(x) is the probability of the even number occur.

The random variable x of even numbers are 12,14,16,18.So n(A)=4

Total outcomes n(S)=7

So P(x)=`(n(A))/(n(S))`

=`4/7` . Please express your views of this topic Convert Decimals to Fractions by commenting on blog.

Random Variable X

random variable x problem 3:

What is the probability of getting a head when a coin is tossed?

Step 1:

The random variable Y contains two possibilities they are head and tail
Step 2:

The random variable is denoted by p(y)

Step 3:

The probability for getting a head is as follows

p(y)=`(n(A))/(n(S))`

Step 4:

The random variable y gives

`p(Y)= 1/2`

random variable x problem 4:

What is the probability of getting a tail when a coin is tossed?

Step 1:

The random variable Y contains two possibilities they are head and tail

Step 2:

The random variable is denoted by p(y)

Step 3:

The probability for getting a tail is as follows

p(y)=`(n(A))/(n(S))`

Step 4:

The random variable y gives

`p(y) =1/2`