Geometry Math Activities

Introduction to Geometry Math Activities:

Geometry math deals problems with segments and construction terms.The term ‘Geometry’ meant for  a study of properties of figures such as shapes and  relationship for them. Geometry is the important branches of Mathematics. In real  life geometry plays very an important role from learning  that the concept of geometry have begun from ancient times. Geometry gives the ideas for many  geometrical shapes and figure construction.

Having problem with Length of Line Segment keep reading my upcoming posts, i will try to help you.

Geometry Math Activities Problems Square:


The area of a square A = side × side

Example 1:
The length of the side of a square table mat is 1 m 25 cm. Find the area for the mat.

Solution:
Length of the side of the square table mat=1m 25cm=125cm.
Hence, area of the mat = 125 × 125 sq cm
= 15625 sq cm

Example 2:
The length of square board side is 14 cm find its area

Solution:
Hence, area of the board = 14*14
=196 cm.
Example 3:
The floor of a room is in the form of a square of side 5 m. Find the perimeter.

Solution:
Side of the square=5m
The perimeter (P) of the floor is given by
P= 4×s
=4×5m = 20m
Thus, the perimeter of the floor of the room is 20 m.

Is this topic sum of the squares formula hard for you? Watch out for my coming posts.

Geometry Math Activities Problems rectangle:


Area of Rectangle =length × Breadth
perimeter of a rectangle = 2 × length + 2 × breadth = 2 × (length + breadth)

Activities Problems Example 1:
The length of a rectangle board  12 cm and its breadth is 5 cm. Find  area for the rectangle.


Solution:
Length of the rectangle = 12 cm
Breadth of the rectangle = 5 cm
Hence, the area of the rectangle = 12×5sq cm=60 sq cm

Activities Problems Example 2 :
The length and breadth of a rectangular blackboard are 200 cm and 100 cm respectively. Find the perimeter.

Solution:
Length of the blackboard ( l) = 200 cm
Breadth of the blackboard (b) = 100 cm
Hence, perimeter (P) of the blackboard is given by
P = 2 × ( l+b)
= 2 × (200 cm + 100 cm)
= 2 × 300 cm = 600 cm
Thus, the perimeter of the blackboard is 600 cm.